At the same temperature, total $K E$ of $16$ grams of methane is _____ times that of $16$ grams of $S O_{2}$ :

Same

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Two times

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Four times

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Three times

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Solution

The correct option is A Four times
At same temperature, for equal masses of gas, $K E$ is inversely proportional to molecular weight of gas.
$\frac{K E_{1}}{K E_{2}} = \frac{64}{16} = \frac{4}{1}$

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