At the top of a mountain, the thermometer reads $0^{\circ} C$ and the barometer reads $700 m m H g$ . At the bottom of the mountain the thermometer reads $30^{\circ} C$ and the pressure $760 m m H g$ . Compare the density of the air at the top with that at the bottom.

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Solution

Density is inversely proportional to volume.
$\frac{d_{t o p}}{d_{b o t t o m}} = \frac{V_{b}}{V_{t}} = \frac{T_{b} P_{t}}{T_{t} P_{b}} = \frac{303 \times 700}{273 \times 760} = \frac{1.02}{1}$ .

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At the top of a mountain, the thermometer reads 0∘C and the barometer reads 700 mm Hg. At the bottom of the mountain the thermometer reads 30∘C and the pressure 760 mm Hg. Compare the density of the air at the top with that at the bottom.

Density is inversely proportional to volume.dtopdbottom=VbVt=TbPtTtPb=303×700273×760=1.021.

At the top of a mountain, the thermometer reads $0^{\circ} C$ and the barometer reads $700 m m H g$ . At the bottom of the mountain the thermometer reads $30^{\circ} C$ and the pressure $760 m m H g$ . Compare the density of the air at the top with that at the bottom.

Density is inversely proportional to volume.
$\frac{d_{t o p}}{d_{b o t t o m}} = \frac{V_{b}}{V_{t}} = \frac{T_{b} P_{t}}{T_{t} P_{b}} = \frac{303 \times 700}{273 \times 760} = \frac{1.02}{1}$ .