Question

At $\theta$ = ${60}^{\circ }$, the value of sec $\theta$ + cosec $\theta$ is ____.

• A. $2+\frac{\sqrt{3}}{2}$
• B. $1+\frac{1}{\sqrt{2}}$
• C. $2+\frac{2}{\sqrt{3}}$
• D. $\frac{2}{\sqrt{2}}$

Answer 1

The correct option is C $2+\frac{2}{\sqrt{3}}$

At $\theta$ = ${60}^{\circ }$,

sec $\theta$ = 2
and
cosec $\theta$ = $\frac{2}{\sqrt{3}}$

$\therefore$ sec $\theta$ + cosec $\theta$
$=2+\frac{2}{\sqrt{3}}$