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Question

At time t=0, a battery of 10 V is connected across point A and B in the given circuit. If the capacitors have no charge initially, the time (in seconds) at which the voltage across them becomes 4 V is (answer upto two decimal places)
[Take ln5=1.6 , ln3=1.1]



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Solution




Q=Q0(1et/RC)
16=40(1et/4)
et4=11640=35
ln35=t4
t=2 s

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