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First Order Reaction

At T'K' temp,...

Question

At T’K’ temp, the half life of a gaseous reaction at an initial pressure of 80 Kpa is 350 s. When the pressure is 40 Kpa, the half life period is 175 sec. What is order of reaction ?

A

1

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B

2

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C

3

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Solution

$n = 1 + \frac{l o g (t_{1 / 2})_{1} - l o g (t_{1 / 2})_{2}}{l o g p_{2} - l o g p_{1}}$
Thus, according to given data
$n = 1 + \frac{l o g (350) - l o g (175)}{l o g (40) - l o g (80)}$
$= 1 + \frac{l o g (2 \times 175) - l o g 175}{l o g 40 - l o g (2 \times 40)}$
$= 1 - 1 = 0$
Thus, n = 0 = Order.

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