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Question

At what altitude will the acceleration due to gravity be 25% of that at the earth's surface (given radius of earth is R)?

A
R/4
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B
R
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C
3R/8
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D
R/2
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Solution

The correct option is C 3R/8
gh=g(12hR)
Now,
gh is 25% of g
gh=25100g=g4
g4=g(12hR)
So, h=3R8

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