At what angle will a ray of light be incident on one face of an equilateral prism, so that the emergent ray may graze the second surface of the prism $(μ = 1.5)$ ?

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Solution

$μ_{g} = \frac{sin i}{sin r_{1}}$
$1.5 = \frac{sin i}{sin r_{1}}$
$\frac{1}{M_{g}} = \frac{sin r_{2}}{sin 90}$
$sin r_{2} = \frac{1}{1.5}$
$r_{2} = {41.8}^{\circ}$
$r_{1} = 60 - 41.8 = 18.18$
$1.5 = \frac{sin i}{sin r_{1}}$
$sin i = 0.468$
$i = {27.9}^{\circ}$

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At what angle will a ray of light be incident on one face of an equilateral prism, so that the emergent ray may graze the second surface of the prism (μ=1.5)?

μg=sinisinr11.5=sinisinr11Mg=sinr2sin90sinr2=11.5r2=41.8∘r1=60−41.8=18.181.5=sinisinr1sini=0.468i=27.9∘

At what angle will a ray of light be incident on one face of an equilateral prism, so that the emergent ray may graze the second surface of the prism $(μ = 1.5)$ ?

$μ_{g} = \frac{sin i}{sin r_{1}}$
$1.5 = \frac{sin i}{sin r_{1}}$
$\frac{1}{M_{g}} = \frac{sin r_{2}}{sin 90}$
$sin r_{2} = \frac{1}{1.5}$
$r_{2} = {41.8}^{\circ}$
$r_{1} = 60 - 41.8 = 18.18$
$1.5 = \frac{sin i}{sin r_{1}}$
$sin i = 0.468$
$i = {27.9}^{\circ}$