At what angles for the first order diffraction, spacing between two planes respectively are $λ$ and $\frac{λ}{2}$ ?

0^{\circ}, 90^{\circ}

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90^{\circ}, 0^{\circ}

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30^{\circ}, 90^{\circ}

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90^{\circ}, 30^{\circ}

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Solution

The correct option is C $30^{\circ}, 90^{\circ}$
$n λ$ = 2d sin $θ$ , where
n = Order of reflection
$λ$ = wave length
$θ$ = Angle of reflection
d = Inter planar distance

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At what angles for the first order diffraction, spacing between two planes respectively are λ and λ2 ?

The correct option is C 30∘,90∘nλ = 2d sinθ, where n = Order of reflection λ = wave length θ = Angle of reflection d = Inter planar distance

At what angles for the first order diffraction, spacing between two planes respectively are $λ$ and $\frac{λ}{2}$ ?

The correct option is C $30^{\circ}, 90^{\circ}$
$n λ$ = 2d sin $θ$ , where
n = Order of reflection
$λ$ = wave length
$θ$ = Angle of reflection
d = Inter planar distance