Question

At what constant rate $P$, ${}^{56}Mn$ nuclei are being produced in the cyclotron during the bombardment?

• A. $2\times {10}^{11}nuclei{s}^{-1}$
• B. $13.86\times {10}^{10}nuclei{s}^{-1}$
• C. $9.6\times {10}^{10}nuclei{s}^{-1}$
• D. $6.93\times {10}^{10}nuclei{s}^{-1}$

Answer 1

The correct option is B $13.86\times {10}^{10}nuclei{s}^{-1}$

${}^{56}Mn+d{\to }^{56}Mn\left(stable\right)+p$

$\therefore$ one radioactive Mn nucleus disintegrates to convert to one stable Mn nucleus .

After long time, the activity of ${}^{56}Mn$ becomes equal to $13.86\times {10}^{10}{s}^{-1}$.

$⟹13.86\times {10}^{10}$ radioactive Mn nucleii get disintegrated in one second.

Thus, $13.86\times {10}^{10}$ stable Mn nucleii are produced in one second.