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Question

At what depth the acceleration due to gravity will become 4.9m/s^2?

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Solution

Let us consider the earth to be a spherical mass of ‘M’ and radius ‘R’. A body of mass ‘m’ is placed initially on the surface and finally taken x distance deep into the earth.
We know acceleration due to gravity on the surface of the earth is

This expression shows that acceleration due to gravity decreases as we go deep into the earth.
At the center of earth x=R, so g’=0. Hence, the acceleration due to gravity at the center of the earth is zero.

given g'=4.9 m divided by s squared
and we know g= 9.8 m divided by s squared , R=6400km
so,
space space space g apostrophe equals g left parenthesis 1 minus x over R right parenthesis rightwards double arrow fraction numerator g apostrophe over denominator g end fraction equals left parenthesis 1 minus x over R right parenthesis rightwards double arrow left parenthesis 1 minus fraction numerator g apostrophe over denominator g end fraction right parenthesis equals x over R rightwards double arrow x equals R left parenthesis 1 minus fraction numerator g apostrophe over denominator g end fraction right parenthesis rightwards double arrow x equals 6400 left parenthesis 1 minus fraction numerator 4.9 over denominator 9.8 end fraction right parenthesis rightwards double arrow x equals 3200 space k m
Hope it helps .


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