At what distance from a concave mirror of focal length 25 cm should an object be placed ? so that the size of image is equal to the size of object ___

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Solution

f = -25 cm

$h_{i}$ = $h_{o}$ => u = v

Mirror formula $\frac{1}{f}$ = $\frac{1}{v}$ + $\frac{1}{u}$

1/25 = $\frac{1}{u}$ + $\frac{1}{u}$

u = 50

The object should be placed at 50 cm from the pole in front of the mirror.

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At what distance from a concave mirror of focal length 25 cm should an object be placed ? so that the size of image is equal to the size of object ___

f = -25 cm hi = ho => u = v Mirror formula 1f = 1v + 1u 1/25 = 1u + 1u u = 50 The object should be placed at 50 cm from the pole in front of the mirror.

f = -25 cm

$h_{i}$ = $h_{o}$ => u = v

Mirror formula $\frac{1}{f}$ = $\frac{1}{v}$ + $\frac{1}{u}$

1/25 = $\frac{1}{u}$ + $\frac{1}{u}$

u = 50

The object should be placed at 50 cm from the pole in front of the mirror.