At What distance from a converging lens of focal length $12 c m$ must an object be placed in order that an image of magnification $1$ will be produced?

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Solution

since magnification( $\frac{- v}{u}$ ) is $1$ , hence image distance(v) = object distance (u)
this will be the case when object is at center of curvature, this gives $u = 2 f = 24 c m$

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At What distance from a converging lens of focal length 12 cm must an object be placed in order that an image of magnification 1 will be produced?

since magnification(−vu) is 1, hence image distance(v) = object distance (u)this will be the case when object is at center of curvature, this gives u=2f=24cm

At What distance from a converging lens of focal length $12 c m$ must an object be placed in order that an image of magnification $1$ will be produced?

since magnification( $\frac{- v}{u}$ ) is $1$ , hence image distance(v) = object distance (u)
this will be the case when object is at center of curvature, this gives $u = 2 f = 24 c m$