At what distance from the centre of a uniformly charged ring, maximum value of electric field will be obtained?

3 m

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5 m

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7 m

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9 m

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Solution

The correct option is B $5 m$
Given:
$λ = + 30 nC/m; R = 5 \sqrt{2} m$

We know that, maximum value of electric field for a ring of uniformly distributed charge over its circumference will be at

$OP = r = \frac{R}{\sqrt{2}}$

$\Rightarrow OP = r = 5 m$

Hence, $(b)$ is correct option.

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At what distance from the centre of a uniformly charged ring, maximum value of electric field will be obtained?

The correct option is B 5 mGiven: λ=+30 nC/m; R=5√2 m We know that, maximum value of electric field for a ring of uniformly distributed charge over its circumference will be at OP=r=R√2 ⇒OP=r=5 m Hence, (b) is correct option.

The correct option is B $5 m$
Given:
$λ = + 30 nC/m; R = 5 \sqrt{2} m$

We know that, maximum value of electric field for a ring of uniformly distributed charge over its circumference will be at

$OP = r = \frac{R}{\sqrt{2}}$

$\Rightarrow OP = r = 5 m$

Hence, $(b)$ is correct option.