Question

At what height above the ground must a body of mass 10kg be situated in order to have potential energy equal in value to the kinetic energy possessed by another body of mass 10kg moving with a velocity of 10m/s

Answer 1

Dear student,
$$\begin{gathered} Potentialenergy=Kineticenergy \\ mgh=\frac{1}{2}m\text{'}{v}^2 \\ 10\times 10\times h=\frac{1}{2}\times 10\times {10}^2 \\ orh=5m \end{gathered}$$

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