At what maximum speed can a car negotiate a turn on a wet road with coefficient of static friction 0.24 without sliding out of control. The radius of the turn is 25 m

17.75 m/s

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5.75 m/s

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7.75 m/s

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5 m/s

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Solution

The correct option is C 7.75 m/s
The car on the curve will have a centripetal force directed towards the centre given by $\frac{m v^{2}}{R}$ AND friction holds the car from moving towards the centre.
Thus $μ m g = m v^{2} / R$ , solving we get, $v = \sqrt{μ R g} = \sqrt{0.24 \times 25 \times 10} = 7.75 m / s$
The correct option is (c)

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At what maximum speed can a car negotiate a turn on a wet road with coefficient of static friction 0.24 without sliding out of control. The radius of the turn is 25 m

The correct option is C 7.75 m/sThe car on the curve will have a centripetal force directed towards the centre given by mv2R AND friction holds the car from moving towards the centre. Thus μmg=mv2/R, solving we get, v=√μRg=√0.24×25×10=7.75m/sThe correct option is (c)