At what point(s) does $f (x) = x^{2} + 3 x + 2$ intersect the $x$ -axis?

(2, 0)

and

(1, 0)

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(0, 2)

and

(0, 1)

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(0, - 1)

and

(0, - 2)

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(- 1, 0)

and

(0, - 2)

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(- 1, 0)

and

(- 2, 0)

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Solution

The correct option is E $(- 1, 0)$ and $(- 2, 0)$
On $x$ -axis, the $y$ -coordinate will be zero.
So, $x^{2} + 3 x + 2 = (x + 1) (x + 2) = 0$
Therefore we get $x = - 1, - 2$
The points are $(- 1, 0), (- 2, 0)$ .

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At what point(s) does f(x)=x2+3x+2 intersect the x-axis?

The correct option is E (−1,0) and (−2,0)On x-axis, the y-coordinate will be zero.So, x2+3x+2=(x+1)(x+2)=0Therefore we get x=−1,−2The points are (−1,0),(−2,0).

At what point(s) does $f (x) = x^{2} + 3 x + 2$ intersect the $x$ -axis?

The correct option is E $(- 1, 0)$ and $(- 2, 0)$
On $x$ -axis, the $y$ -coordinate will be zero.
So, $x^{2} + 3 x + 2 = (x + 1) (x + 2) = 0$
Therefore we get $x = - 1, - 2$
The points are $(- 1, 0), (- 2, 0)$ .