At what pressure the volume would 1/3rd of the volume occupied by a gas under 875mm pressure of Hg at 15 degrreeC.assume Temperature is conatant

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Dear Student,

$Let the initial volume be V_{1} So, Final volume, V_{2} = \frac{1}{3} V_{1} and, P_{1} = 875 mm P_{2} = ? At constant temperature, P_{1} V_{1} = P_{2} V_{2} or, P_{2} = \frac{P_{1} V_{1}}{V_{2}} or, P_{2} = \frac{875 \times V_{1}}{\frac{1}{3} V_{1}} = 3 \times 875 = 2625 mm$

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At what pressure the volume would 1/3rd of the volume occupied by a gas under 875mm pressure of Hg at 15 degrreeC.assume Temperature is conatant

Dear Student, Let the initial volume be V1So, Final volume, V2 =13V1and, P1= 875 mmP2=?At constant temperature, P1V1= P2V2or, P2=P1V1V2or, P2=875×V113V1=3×875=2625 mm

Dear Student,

$Let the initial volume be V_{1} So, Final volume, V_{2} = \frac{1}{3} V_{1} and, P_{1} = 875 mm P_{2} = ? At constant temperature, P_{1} V_{1} = P_{2} V_{2} or, P_{2} = \frac{P_{1} V_{1}}{V_{2}} or, P_{2} = \frac{875 \times V_{1}}{\frac{1}{3} V_{1}} = 3 \times 875 = 2625 mm$