At what relative humidities, will $N a_{2} S O_{4}$ be deliquescent (i.e absorb moisture) when exposed to the air at $0^{\circ}$ C?

Above 33.33%

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Below 33.33%

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Above 66.66%

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Below 66.66%

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Solution

The correct option is B Above 33.33%
The vapour pressure of water is $0.00605$ atm at $0^{\circ} C$ . When relative humidity is $33.33$ % the partial pressure of water is $0.002$ atm.
When relative humidity is higher than this, $N a_{2} S O_{4} \cdot 10 H_{2} O$ will absorb moisture.

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