At what relative humidities will Na2SO4⋅10H2O be efflorescent (release moisture) when exposed to air at 0∘C?
A
Above 33.33%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Below 33.33%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Above 66.66%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Below 66.66%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B Below 33.33% The vapour pressure of water is 0.00605 atm at 0∘C. When relative humidity is 33.33% the partial pressure of water is 0.002 atm. When relative humidity is lower than this, Na2SO4⋅10H2O will release moisture.