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Ideal Gas Equation

At what tempe...

Question

At what temperature $28 g$ of $N_{2}$ will occupy a volume of $20 l i t r e s$ at $2 a t m$ ?

300.0 K

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487.2 K

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289.6 K

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382.8 K

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Solution

The correct option is B $487.2 K$
$P V = n R T$ or $T = \frac{P V}{n R} (n = \frac{m}{M})$
Here, mass of nitrogen $m = 28 g$
Volume of nitrogen $V = 20 l i t r e s$
Pressure $P = 2 a t m$
$∴ T = \frac{2 \times 20 \times 28}{28 \times 0.0821} = 487.2 K$ .

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