wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

At what temperature does the rms speed of oxygen molecules equal the escape velocity of - (i) Earth, (ii) the Moon? Assume gravitational acceleration at the moon is 0.6g.


A

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D


Putting the values of R and gravitational acceleration in the expression of ve,

vEarthe=11200 m/s

vMoone=2380 m/s

The molar mass of O2 is 32gms, or 0.032kgs. Now from kinetic theory,

vrms=3RTM

T=[Mv2rms3R].

(i) For vrms of O2 to be vEarthe

T=[0.032×(11200)23×8.314]K

=1.61×105K.

(ii) For vrms of O2 to be vMoone

T=[0.032×(2380)23×8.314]K

=7.27×103K.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equations Redefined
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon