Question

At What temperature in the celsius scale, V (volume) of a certain mass of gas at ${27}^{\circ }$ C will be doubled keeping the pressure constant

• A. 54° C
• B. 327° C
• C. 427° C
• D. 527° C

Answer 1

The correct option is B

327° C

$\frac{V_1}{V_2}$ = $\frac{T_1}{T_2}$ $\therefore$ $T_2$ = $\frac{T_1{V}_2}{V_1}$ = ${300}^{\circ }$ K , $\frac{2V}{V}$ = ${600}^{\circ }$ K

$T_2$ = ${600}^{\circ }$ K = $(600-273{)}^{\circ }$ C = ${327}^{\circ }$C