At what temperature is the Celsius and Fahrenheit equal, if the relation between Celsius and Fahrenheit is
$\frac{F - 32}{9} = \frac{C}{5}$

40 degree

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-40 degree

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0 degree

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100 degree

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Solution

The correct option is B
-40 degree

We use relationship $\frac{F - 32}{9} = \frac{C}{5}$ . We substitute both F and C as 'X' in the relationship equation as Celsius and Fahrenheit are equal according to question.
On solving the equation,
$\frac{X - 32}{9} = \frac{X}{5}$
$\Rightarrow 5 X - 160 = 9 X$
$\Rightarrow - 4 X = 160 o r X = - 40$

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Similar questions

At what temperature is the Celsius and Fahrenheit equal, if the relation between Celsius and Fahrenheit is
$\frac{F - 32}{9} = \frac{C}{5}$

32

(^{o} F)

(^{o} C)

^{c} C = \frac{5 F - 160}{9}

0^{o}

0^{o}

Temperature in Fahrenheit is given as,

$\frac{C}{5} = \frac{F - 32}{9}$

Where C and F are temperatures in Celsius and Fahrenheit respectively.

What is the temperature in Fahrenheit if it is 45 degrees Celsius?

68^{o} F

77^{o} F

F = \frac{9}{5} C + 32 ?

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