Question

at what temperature is the Fahrenheit scale reading equal to twice of Celsius scale reading?

Answer 1

$$\begin{gathered} \mathbf{Relation}\mathbf{}\mathbf{between}\mathbf{}\mathbf{Fahrenheit}\mathbf{}\mathbf{and}\mathbf{}\mathbf{Celsius}\mathbf{}\mathbf{scale}\mathbf{:} \\ \frac{\mathbf{F}\mathbf{-}\mathbf{32}}{\mathbf{180}}\mathbf{=}\frac{\mathbf{C}}{\mathbf{100}} \\ \mathrm{Given}\mathrm{that}\mathrm{F}=2\mathrm{C} \\ \mathrm{Let} \\ \mathrm{C}=\mathrm{x}\mathrm{and}\mathrm{F}=2\mathrm{x} \\ \mathrm{Hence}, \\ \frac{2\mathrm{x}-32}{180}=\frac{\mathrm{x}}{100} \\ 2\mathrm{x}-32=\frac{9\mathrm{x}}{5} \\ 2\mathrm{x}-32=1.8\mathrm{x} \\ 0.2\mathrm{x}=32 \\ \mathrm{x}=\frac{32}{0.2} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{=}{\mathbf{160}}^{\mathbf{o}} \end{gathered}$$