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Question

At what temperature KE of a gas molecules is half of its value at 327c?


A

13.5c

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B

150c

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C

27c

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D

123c

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Solution

The correct option is

C

27c

Kinetic energy of a gas molecule

E = 3/2kT

where k is Boltzmann's constant.

∴E∝T

E1E2=T1T2

EE2=600T2T2=300k or 27c


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