wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

At what temperature liquid water will be in equilibrium with water vapour?
ΔHvap=40.73 kJ mol1, ΔSvap=0.109 kJ K1 mol1,

A
282.4 K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
373.6 K
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
100 K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
400 K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 373.6 K
The given reaction is :-
H2O(l)H2O(g)
Now, at equilibrium, G=0
Now, from fibb's free energy change equation
G=HTS
H=TS
T=HS=40.730.1079=373.6K
(Hrap=40.73KJ/mol,Srap=0.109KJK1mol1)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon