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Standard XII

Chemistry

Arrhenius Equation

At what tempe...

Question

At what temperature, rate constant is equal to pre-exponential factor ?

T = \frac{1.25 \times 10^{4} K}{14}

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T = \infty

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T = 0

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T = (14 - 1.25 \times 10^{4}) K

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Solution

The correct option is B $T = \infty$
As we know,
$l o g k = l o g A - E_{a} / 2.303 R T$
$K = A$ , when $T = \infty$ .

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Similar questions

Q. The rate constant for the decomposition of a certain reaction is described by the equation

l o g k (s^{- 1}) = 14 - \frac{1.25 \times 10^{4} K}{T}

Energy of activation (in

k c a l

) is:

The rates of chemical reactions are strongly affected by temperature. Arrhenius (1889) gave following relation between rate constant and temperature:

k = A e^{- E_{a} / R T}

This equation is called Arrhenius equation. The constant '

A

' is called Arrhenius constant or pre-exponential factor.

The logarithm of Arrhenius equation is:

{log}_{10} k = {log}_{10} A - \frac{E_{a}}{2.303 R T}

This equation for a reaction is:

{log}_{10} k = 14 - \frac{1.25 \times 10^{4} K}{T}

Energy of activation in

k

c a l

{m o l}^{- 1}

is:

The rate constant for the first order decomposition of $H_{2} O_{2}$ is given by the following equation, $l o g k = 14.34 - 1.25 \times 10^{4} K / T$ . Calculate $E_{a}$ for this reaction and at what temperature will its half-life period be 256 minutes?

Q. For the first order reaction,

2 H_{2} O_{2} \to 2 H_{2} + O_{2} log k = 14.34 - 1.25 \times 10^{4} K / T

. The energy of activation for the above reaction if its half life period is 256 min.

Q. For a first order reaction,

A \to P

, the temperature (T) dependent rate constant (k) was formed to follow the equation

l o g_{10} k = - \frac{2000}{T} + 6.0

. The pre-exponential factor A and activation energy

E_{a}

, respectively are:

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At what temperature, rate constant is equal to pre-exponential factor ?

The correct option is B T=∞As we know,logk=logA−Ea/2.303RTK=A, when T=∞.

The correct option is B $T = \infty$
As we know,
$l o g k = l o g A - E_{a} / 2.303 R T$
$K = A$ , when $T = \infty$ .