Question

At what temperature, the volume of 'V' of a certain mass of gas at ${37}^{o}C$ be doubled?
(keeping pressure constant).

• A. ${527}^{o}C$
• B. 620 K
• C. ${347}^{o}C$
• D. ${347}^{o}F$

Answer 1

Answer: (B), (C)

${347}^{o}C$
620 K

At constant pressure,

$V\alpha T$

$\therefore \frac{V_1}{V_2}=\frac{T_1}{T_2}$

$V_1=V;V_2=2V$

$T_1={37}^{o}C;T_2=?$

$=37+273=310K$

$\frac{V}{2V}=\frac{210}{T_2}$

$T_2=310\times 2=620K.$

$C=K-273$

$C=620-273={347}^{o}C$

$\frac{F-32}{180}=\frac{(620-273)}{100}$

$F=(\frac{9}{5}\times 347)+32$

$=624.6+32$

$={656.6}^{o}F$