Question

At what temperature, the volume of '$V^{\prime }$ of a certain mass of gas at ${37}^{o}C$ be doubled? (keeping pressure constant)

• A. ${527}^{o}C$
• B. ${620}^{o}C$
• C. ${347}^{o}C$
• D. ${347}^{o}F$

Answer 1

Answer: (C)

${347}^{o}C$

$\frac{V_1}{T_1}=\frac{V_2}{T_2}⟹\frac{V_1}{(273+37)K}=\frac{2V_1}{T_2}⟹T_2=620K=347℃$