At what temperature under constant volume, the pressure of a gas is double to that at 0∘C ?
A
273K
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B
546∘C
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C
273∘C
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D
136.5∘C
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Solution
The correct option is C273∘C According to Gay-Lussac's law for constant volume, the pressure of given mass of gas is directly proportional to its absolute temperature. i.e P∝T Given, P2=2P1T1=0∘C=273K∴P1T1=P2T2⇒T2=P2P1×T1=2×273K=546K⇒T2=(546−273)∘C⇒T2=273∘C