At what temperature will the average speed of $C H_{4}$ molecules have the same value as $O_{2}$ has at 300 K

1200 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

150 K

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

600 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

300 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
150 K

$\frac{V_{a v} C H_{4}}{V_{a b} O_{2}} = \sqrt{\frac{T_{C H_{4}}}{T_{O_{2}}}} = 1$

$\frac{T_{C H_{4}}}{300} . \frac{32}{16} = 1; T_{C H_{4}} = 150^{\circ} K$

Suggest Corrections

Similar questions

C H_{4}

O_{2}

300 K

At what temperature, the translational kinetic energy of 14 g of nitrogen will be the same as that of 32g of oxygen at 300 K

S O_{2}

O_{2}

300 K

4 L

300 k

6 atmospheres

47^{0}

Join BYJU'S Learning Program