At what temperature will the average speed of $C H_{4}$ molecules have the same value as $O_{2}$ has at 300 K.

1200 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

150 K

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

600 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

300 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
150 K

$\frac{V_{a v} C H_{4}}{V_{a b} O_{2}}$ = $\sqrt{\frac{T_{C H_{4}}}{T_{O_{2}}} \times \frac{M_{O_{2}}}{M_{C H_{4}}}}$ =1 $\frac{T_{C H_{4}}}{300} \times \frac{32}{16}$ = 1 ; $T_{C H_{4}}$ = 150K

Suggest Corrections

Similar questions

C H_{4}

O_{2}

300 K

The temperature at which RMS velocity of $S O_{2}$ molecules is half that of He molecules at 300 K is

S O_{2}

O_{2}

300 K

47^{0}

O_{2}

16

H_{2}

O_{2}

E,

H_{2}

Join BYJU'S Learning Program