At what temperature will the oxygen molecules have the same root mean square speed as hydrogen molecules at 200 K

800 K

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1600 K

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2400 K

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3200 K

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Solution

The correct option is D
3200 K

$v = \sqrt{\frac{3 R T}{M}} \Rightarrow T \propto M \frac{T_{O}}{T_{H}} = \frac{M_{O}}{M_{H}} = 16 \Rightarrow T_{O} = 16 \times 200 = 3200 K$

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