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Fluorides of Xenon

At what tempe...

Question

At what temperature will the total KE of 0.30 mole of He be the same as the total KE of 0.40 mole of Ar at 400 K?

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Solution

The correct option is A

Kinetic Energy of $n$ moles = $\frac{3}{2} n R T$

$R$ = gas constant , $T$ = temperature

$\Rightarrow n_{1} T_{1} = n_{2} T_{2}$ or $n_{H e} T_{H e} = n_{A r} T_{A r}$

Put the value of $n_{H e} = 0.30$ $n_{A r} = 0.40$ $T_{A r} = 400 K$ in the formula, we get

$T_{H e}$ = $533 K$

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