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Question

At what value of m1 will 8 kg mass be at rest.

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Solution

The FBDs of the different masses and pulley are as shown


Since, 8 kg block will be at rest,
8g=2T T=40 N
Let the acceleration of m1 and 5 kg blocks be a
from the FBDs we get
5gT=5×a a=50405=2 m/s2
Now, we have
Tm1g=m1×2 m1=4010+2
m1=103 kg

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