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Question

At which height from earth surface acceleration due to gravity is decreased by 75% of its value at earth surface?

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Solution

Since, the acceleration due to gravity reduces by 75%, then the value of acceleration due to gravity there is = 100 - 75= 25%.

It means, g' = 25/100 g.

If h is the height of location above the surface of earth(here h is not very less than R, therefore), then

g=g(1+hR)2

gg=1(1+hR)2

25100=1(1+hR)2

1+hR=2

R+h=2R

h=R

Therefore at R = 6400 km from earth surface acceleration due to gravity is decreased by 75% of its value at earth surface.


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