At which value of n the formation of six membered ring takes place ?

n=2

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n=3

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n=-5

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n=6

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Solution

The correct option is C n=3

(Refer to Image 1)
Thus on compare the product with $6$ - membered ring
(Refer to Image 2)
So, $n = 3$ .

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S_{n} = \frac{n}{(n + 1) (n + 2)} + \frac{n}{(n + 2) (n + 4)} + \frac{n}{(n + 3) (n + 6)} + . . . . . . + \frac{1}{6 n}

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