Question

Atmospheric pressures recorded in different cities are as follows :
$\begin{array}{ccccc}\text{Cities}& \text{Shimla}& \text{Bangalore}& \text{Delhi}& \text{Mumbai}\\ p{\text{in N/m}}^2& 1.01\times {10}^5& 1.2\times {10}^5& 1.02\times {10}^5& 1.21\times {10}^5\end{array}$
Consider the above data and mark the place at which liquid will boil first.

• A. Shimla
• B. Bangalore
• C. Delhi
• D. Mumbai

Answer 1

The correct option is A Shimla

The boiling point of a liquid is defined as the temperature at which vapour pressure of liquid becomes equal to the atmospheric pressure. So, lower is the atmospheric pressure, lower is the boiling point of liquid, which means lower temperature will be required to boil the same amount of liquid. According to give data, Shimla has lowest atmospheric pressure, hence liquid will boil first in this city as lesser temperature will be required to boil the liquid.