Atomic mass of boron is 10.81. It has two isotopes with 80% and 20% abundance respectively. The atomic mass of the isotope having 80% abundance is 11.01. The atomic mass of the other isotope is:

10.81

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11.01

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10.01

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21.82

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Solution

The correct option is C 10.01
Let the mass of other isotope be x
$∴ 10.81 \times 100 = 11.01 \times 80 + 20 \times x$
$\Rightarrow x = 10.01$ . Thus the mass of other isotope is $10.01$ . Hence answer is option C.

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Atomic mass of boron is 10.81. It has two isotopes with 80% and 20% abundance respectively. The atomic mass of the isotope having 80% abundance is 11.01. The atomic mass of the other isotope is:

The correct option is C 10.01Let the mass of other isotope be x∴10.81×100=11.01×80+20×x⇒x=10.01. Thus the mass of other isotope is 10.01. Hence answer is option C.

The correct option is C 10.01
Let the mass of other isotope be x
$∴ 10.81 \times 100 = 11.01 \times 80 + 20 \times x$
$\Rightarrow x = 10.01$ . Thus the mass of other isotope is $10.01$ . Hence answer is option C.