Atomic number of a transition metal is 25 then its magnetic moment in its +3 oxidation state is:

1.73 BM

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2.84 BM

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4.9 BM

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5.9 BM

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Solution

The correct option is C 4.9 BM
manganese in +3 oxidation state has 4 unpaired electrons
Magnetic moment $= \sqrt{n (n + 2)}$
$= \sqrt{4 \times 6}$
$= \sqrt{24}$
$= 4.9 B M$

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