Atomic number of $A g$ is $47$ . In the same group, the atomic number of elements placed above and below $A g$ in the long form of periodic table will be $x$ and $y$ respectively. Give the value of $\frac{x + y}{12}$ .

8

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Solution

The correct option is B $9$
$C u$ and $A u$ are the elements lying above and below $A g$ in the periodic table. In order to get the atomic number of $A u$ , add $32$ since it belongs to the $6^{t h}$ period (which is having lanthanide elements also). To get the atomic number of $C u$ , subtract $18$ from the atomic number of $A g$ since $C u$ belongs to the $4^{t h}$ period in the periodic table.
$C u = 47 - 18 = 29 (x)$
$A u = 47 + 32 = 79 (y)$
The value of $\frac{x + y}{12} = \frac{29 + 79}{12} = 9$

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Atomic number of Ag is 47. In the same group, the atomic number of elements placed above and below Ag in the long form of periodic table will be x and y respectively. Give the value of x+y12.

Atomic number of $A g$ is $47$ . In the same group, the atomic number of elements placed above and below $A g$ in the long form of periodic table will be $x$ and $y$ respectively. Give the value of $\frac{x + y}{12}$ .