Question

Atomic number of Ag is 47. In the same group, the atomic numbers of elements placed above and below in long form of periodic table will be :

• A. 29, 65
• B. 39, 79
• C. 29, 79
• D. 39, 65

Answer 1

The correct option is C 29, 79

$Ag$ with atomic number $47$ is present in the $d-block$. Element above $Ag$ is $47-18=29$, element with atomic number $29$,i.e.; $Cu$ and element below $Ag$ is $79$ which is atomic number of $Au$

The element should have been $47+18=65$ $\left(Tb\right)$, but is present in lanthanides$⟶$ inner transition elements.