Atomic numbers of nitrogen, oxygen and fluorine are 7, 8 and 9 respectively. Write the electronic configuration of each element and answer the following question:
What is the number of valence electrons of F?
Atomic numbers of nitrogen, oxygen and fluorine are 7, 8 and 9 respectively. Write the electronic configuration of each element and answer the following question:
What is the number of valence electrons of F?
Step-1: Introduction
The elements in periodic table are placed in periods and groups. Periods are horizontal rows that has increasing atomic numbers. Groups are vertical columns. There are 7 periods and 18 groups in periodic table.
Step-2: Electronic configuration
Atomic numbers of Nitrogen (), Oxygen () and Fluorine () are 7, 8 and 9 respectively.
Electronic configuration of Nitrogen = (2, 5)
Electronic configuration of Oxygen = (2, 6)
Electronic configuration of Fluorine = (2, 7)
Step-3: Valence electrons of Fluorine
The electrons in the valence shell of the element is valence electrons.
Fluorine has 2 electrons in K-shell and 7 electrons in L-shell. Since L-shell is valence shell, it has 7 valence electrons.
Therefore, the number of valence electrons in Fluorine is 7.
Step-1: Introduction
The elements in periodic table are placed in periods and groups. Periods are horizontal rows that has increasing atomic numbers. Groups are vertical columns. There are 7 periods and 18 groups in periodic table.
Step-2: Electronic configuration
Atomic numbers of Nitrogen (), Oxygen () and Fluorine () are 7, 8 and 9 respectively.
Electronic configuration of Nitrogen = (2, 5)
Electronic configuration of Oxygen = (2, 6)
Electronic configuration of Fluorine = (2, 7)
Step-3: Valence electrons of Fluorine
The electrons in the valence shell of the element is valence electrons.
Fluorine has 2 electrons in K-shell and 7 electrons in L-shell. Since L-shell is valence shell, it has 7 valence electrons.
Therefore, the number of valence electrons in Fluorine is 7.
