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Modern Periodic Table

Atomic radius...

Question

Atomic radius of which element has the least value in $2^{n d}$ period ?

A

Hydrogen

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B

Florine

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C

Neon

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D

Helium

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Solution

The correct option is B Florine
As we move from left to right, atomic size decreases because of increase in nuclear charge but no change in the shells. Hence, Last element will be the smallest element in the period. Hence, fluorine has small radius in the second period. Noble gases are exception to this property.

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(i) F, Cl, Br (ii) Li, Na, K	.................... ....................	.................... ....................

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