Atoms $A$ present at corners and atoms $B$ present at centre of each face. then what is the formula.

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Solution

Corner atoms $(A)$ contribute $= \frac{1}{8}$ of each atom.
Face center atoms $(B)$ contribute $= \frac{1}{2}$ of each atom.
Therefore, formula will be $A B_{4}$ .

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Atoms A present at corners and atoms B present at centre of each face. then what is the formula.

Corner atoms (A) contribute =18of each atom.Face center atoms (B) contribute =12of each atom.Therefore, formula will be AB4.

Atoms $A$ present at corners and atoms $B$ present at centre of each face. then what is the formula.

Corner atoms $(A)$ contribute $= \frac{1}{8}$ of each atom.
Face center atoms $(B)$ contribute $= \frac{1}{2}$ of each atom.
Therefore, formula will be $A B_{4}$ .