Atoms of element B from HCP lattice and those of element A occupy two thirds of tetrahedral voids. What is the formula of the compound formed by elements A and B.

A₄B₃

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A₄B₆

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A₈B₃

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A₅B₃

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Solution

The correct option is A
A₄B₃

The number of tetrahedral voids formed is equal to twice the number of atoms of element B. But only 2/3 of these tetrahedral voids are occupied by atoms of element A.

Therefore the ratio of number of atoms of A and B is

2x(2/3) : 1 = 4:3

The formula of compound is $A_{4} B_{3}$

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