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Question
ATP = ADP ∼P hypothesis was given by Lipman in
ATP = ADP ∼P hypothesis was given by Lipman in
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Solution
The correct option is A 1941
The hypothesis of the breaking of ATP was given by Lipman in the year 1941. ATP is formed by the combination of adenine as a nitrogenous base, ribose sugar, and triphosphate. It is found in free cells which breaks to form energy by breaking it's high energy phosphate bonds. The high energy phosphate bonds break to form ADP and AMP.ATP has three phosphates out of which one is directly attached to the ribose with phosphate ester bond and it is low energy bond. The bond between two phosphate groups is a phosphoanhydride bond which is considered as high energy bond. So ATP has only two high energy bond phosphoanhydride bond.So, the correct answer is option A.
The hypothesis of the breaking of ATP was given by Lipman in the year 1941. ATP is formed by the combination of adenine as a nitrogenous base, ribose sugar, and triphosphate. It is found in free cells which breaks to form energy by breaking it's high energy phosphate bonds. The high energy phosphate bonds break to form ADP and AMP.
ATP has three phosphates out of which one is directly attached to the ribose with phosphate ester bond and it is low energy bond. The bond between two phosphate groups is a phosphoanhydride bond which is considered as high energy bond. So ATP has only two high energy bond phosphoanhydride bond.
So, the correct answer is option A.
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