Question

Attacking or electrophilic species in nitration of benzene is :

• A. $N{O}_2^{-}$
• B. $N{O}_2^{+}$
• C. $N{O}_3^{-}$
• D. $N{O}^{+}$

Answer 1

The correct option is B $N{O}_2^{+}$

Electrophilic species in nitration of benzene is $N{O}_2^{+}.$
Generation of electrophile
$HN{O}_3+H_{2}S{O}_4^{-}\to H_{2}O+\underset{\text{Nitration ion}\left(\text{attacking species}\right)}{N{O}_2^{+}}+HS{O}_4^{-}$
$H_{2}S{O}_4$ serves as the acid and $HN{O}_3$ as the base.