Attendance of a class of 45 boys for 10days is given as 40, 42, 30, 35, 45, 44, 41, 38, 44 and 41, then the mean attendance of a class is

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Solution

The correct option is B 40
$M e a n = \frac{s u m o f 10 d a y s a t t e n d a n c e}{n o . o f d a y s}$
$\Rightarrow \frac{40 + 42 + 30 + 35 + 45 + 44 + 41 + 38 + 44 + 41}{10}$
$\Rightarrow \frac{400}{10} = 40$

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