average atomic mass of magnesium is 24.31 amu. this magnesium is composed of 79 mole % of Mg-24 and remaining 21 mole % of Mg-25. calculate mole % of Mg-26.

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Dear Gracy,

$A v e r a g e a t o m i c m a s s c a n b e c a l c u l a t e d i n t h e f o l l o w i n g m a n n e r : A v e r a g e a t o m i c m a s s o f M g = \frac{(m_{1} x_{1} + m_{2} x_{2} + m_{3} x_{3})}{x_{1} + x_{2} + x_{3}} W h e r e m_{1}, m_{2} a n d m_{3} a r e t h e a t o m i c m a s s o f d i f f e r e n t i s o t o p s & x_{1}, x_{2} a n d x_{3} a r e t h e m o l e p e r c e n t . G i v e n A v e r a g e a t o m i c m a s s o f m a g n e s i u m i s 24.31 a . m . u . T h i s m a g n e s i u m i s c o m p o s e d o f 79 m o l e % o f 24 M g a n d r e m a i n i n g 21 m o l e % o f 25 M g & 26 M g . C a l c u l a t e m o l e % o f M g 26 . L e t m o l e p e r c e n t o f 25 M g i s' a' & m o l e p e r c e n t o f 26 M g i s' 21 - a' P u t t h e v a l u e s i n a b o v e e q u a t i o n 24.31 = \frac{[24 \times 79 + 25 a + 26 (21 - a)]}{100} a = 11 s o t h e m o l e p e r c e n t o f 25 M g i s 11 a n d 26 M g i s 21 - 11 = 10 . M o l e p e r c e n t o f 26 M g i s 10$

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